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2x(x-2)=6x^2-5x
We move all terms to the left:
2x(x-2)-(6x^2-5x)=0
We multiply parentheses
2x^2-4x-(6x^2-5x)=0
We get rid of parentheses
2x^2-6x^2-4x+5x=0
We add all the numbers together, and all the variables
-4x^2+x=0
a = -4; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-4)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-4}=\frac{-2}{-8} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-4}=\frac{0}{-8} =0 $
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